Search a number
-
+
211484113 is a prime number
BaseRepresentation
bin11001001101011…
…11110111010001
3112201221111122221
430212233313101
5413114442423
632552501041
75145404521
oct1446576721
9481844587
10211484113
11a9417165
125a9aa781
1334a78539
1420131681
1513876e5d
hexc9afdd1

211484113 has 2 divisors, whose sum is σ = 211484114. Its totient is φ = 211484112.

The previous prime is 211484071. The next prime is 211484123. The reversal of 211484113 is 311484112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119093569 + 92390544 = 10913^2 + 9612^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211484113 is a prime.

It is not a weakly prime, because it can be changed into another prime (211484123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105742056 + 105742057.

It is an arithmetic number, because the mean of its divisors is an integer number (105742057).

Almost surely, 2211484113 is an apocalyptic number.

It is an amenable number.

211484113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211484113 is an equidigital number, since it uses as much as digits as its factorization.

211484113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 768, while the sum is 25.

The square root of 211484113 is about 14542.4933556801. The cubic root of 211484113 is about 595.7891400457.

Subtracting 211484113 from its reverse (311484112), we obtain a palindrome (99999999).

The spelling of 211484113 in words is "two hundred eleven million, four hundred eighty-four thousand, one hundred thirteen".