Base | Representation |
---|---|
bin | 1001100111100010111111… |
… | …00111000100110011111111 |
3 | 2202212220220110201012220211 |
4 | 10303301133213010303333 |
5 | 10233010221344404401 |
6 | 112552104135053251 |
7 | 4312016200430605 |
oct | 463613747046377 |
9 | 82786813635824 |
10 | 21150023044351 |
11 | 68147466a06a3 |
12 | 2457023b11227 |
13 | ba5591839a26 |
14 | 531949133875 |
15 | 26a26222e951 |
hex | 133c5f9c4cff |
21150023044351 has 2 divisors, whose sum is σ = 21150023044352. Its totient is φ = 21150023044350.
The previous prime is 21150023044261. The next prime is 21150023044399. The reversal of 21150023044351 is 15344032005112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21150023044351 is a prime.
It is a super-2 number, since 2×211500230443512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21150023054351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10575011522175 + 10575011522176.
It is an arithmetic number, because the mean of its divisors is an integer number (10575011522176).
Almost surely, 221150023044351 is an apocalyptic number.
21150023044351 is a deficient number, since it is larger than the sum of its proper divisors (1).
21150023044351 is an equidigital number, since it uses as much as digits as its factorization.
21150023044351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 21150023044351 its reverse (15344032005112), we get a palindrome (36494055049463).
The spelling of 21150023044351 in words is "twenty-one trillion, one hundred fifty billion, twenty-three million, forty-four thousand, three hundred fifty-one".
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