2115024451101 has 6 divisors (see below), whose sum is σ = 3055035318270. Its totient is φ = 1410016300728.

The previous prime is 2115024451081. The next prime is 2115024451217. The reversal of 2115024451101 is 1011544205112.

2115024451101 is a `hidden beast` number, since 2 + 1 + 1 + 502 + 4 + 4 + 51 + 101 = 666.

It can be written as a sum of positive squares in only one way, i.e., 1960910105625 + 154114345476 = 1400325^2 + 392574^2 .

It is not a de Polignac number, because 2115024451101 - 2⁵ = 2115024451069 is a prime.

It is a super-3 number, since 3×2115024451101³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2115024451601) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 117501358386 + ... + 117501358403.

It is an arithmetic number, because the mean of its divisors is an integer number (509172553045).

Almost surely, 2^{2115024451101} is an apocalyptic number.

It is an amenable number.

2115024451101 is a deficient number, since it is larger than the sum of its proper divisors (940010867169).

2115024451101 is a wasteful number, since it uses less digits than its factorization.

2115024451101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 235002716795 (or 235002716792 counting only the distinct ones).

The product of its (nonzero) digits is 1600, while the sum is 27.

Adding to 2115024451101 its reverse (1011544205112), we get a palindrome (3126568656213).

The spelling of 2115024451101 in words is "two trillion, one hundred fifteen billion, twenty-four million, four hundred fifty-one thousand, one hundred one".