Base | Representation |
---|---|
bin | 11110110001110010011… |
… | …101001100001000001111 |
3 | 21111012022001201220200011 |
4 | 132301302131030020033 |
5 | 234123102301222421 |
6 | 4255345440414051 |
7 | 305543523523234 |
oct | 36616235141017 |
9 | 7435261656604 |
10 | 2115044164111 |
11 | 745a9232306a |
12 | 2a1ab0017327 |
13 | 1245a8ab3b68 |
14 | 7452394d78b |
15 | 3a03cd524e1 |
hex | 1ec7274c20f |
2115044164111 has 2 divisors, whose sum is σ = 2115044164112. Its totient is φ = 2115044164110.
The previous prime is 2115044164097. The next prime is 2115044164151. The reversal of 2115044164111 is 1114614405112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2115044164111 is a prime.
It is a super-2 number, since 2×21150441641112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2115044164151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057522082055 + 1057522082056.
It is an arithmetic number, because the mean of its divisors is an integer number (1057522082056).
Almost surely, 22115044164111 is an apocalyptic number.
2115044164111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2115044164111 is an equidigital number, since it uses as much as digits as its factorization.
2115044164111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 31.
Adding to 2115044164111 its reverse (1114614405112), we get a palindrome (3229658569223).
The spelling of 2115044164111 in words is "two trillion, one hundred fifteen billion, forty-four million, one hundred sixty-four thousand, one hundred eleven".
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