Base | Representation |
---|---|
bin | 11110110001110110011… |
… | …100101111100100111111 |
3 | 21111012110201210110022101 |
4 | 132301312130233210333 |
5 | 234123221423443111 |
6 | 4255400232325531 |
7 | 305545266121036 |
oct | 36616634574477 |
9 | 7435421713271 |
10 | 2115111156031 |
11 | 74601711a095 |
12 | 2a1b0a5438a7 |
13 | 1245b993b453 |
14 | 7452c7cb71d |
15 | 3a043b86bc1 |
hex | 1ec7672f93f |
2115111156031 has 8 divisors (see below), whose sum is σ = 2120119365744. Its totient is φ = 2110106581440.
The previous prime is 2115111156013. The next prime is 2115111156089. The reversal of 2115111156031 is 1306511115112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2115111156031 is a prime.
It is a super-3 number, since 3×21151111560313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2115111156731) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 258076 + ... + 2072878.
It is an arithmetic number, because the mean of its divisors is an integer number (265014920718).
Almost surely, 22115111156031 is an apocalyptic number.
2115111156031 is a deficient number, since it is larger than the sum of its proper divisors (5008209713).
2115111156031 is a wasteful number, since it uses less digits than its factorization.
2115111156031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1817561.
The product of its (nonzero) digits is 900, while the sum is 28.
The spelling of 2115111156031 in words is "two trillion, one hundred fifteen billion, one hundred eleven million, one hundred fifty-six thousand, thirty-one".
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