Base | Representation |
---|---|
bin | 10011101100101101… |
… | …111101111000010001 |
3 | 2000121001222111200122 |
4 | 103230231331320101 |
5 | 321304220421342 |
6 | 13414454400025 |
7 | 1346102304254 |
oct | 235455757021 |
9 | 60531874618 |
10 | 21151342097 |
11 | 8a74421416 |
12 | 4123660015 |
13 | 1cc1093852 |
14 | 104918b09b |
15 | 83bd944d2 |
hex | 4ecb7de11 |
21151342097 has 2 divisors, whose sum is σ = 21151342098. Its totient is φ = 21151342096.
The previous prime is 21151342061. The next prime is 21151342099. The reversal of 21151342097 is 79024315112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20495930896 + 655411201 = 143164^2 + 25601^2 .
It is a cyclic number.
It is not a de Polignac number, because 21151342097 - 26 = 21151342033 is a prime.
Together with 21151342099, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (21151342099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10575671048 + 10575671049.
It is an arithmetic number, because the mean of its divisors is an integer number (10575671049).
Almost surely, 221151342097 is an apocalyptic number.
It is an amenable number.
21151342097 is a deficient number, since it is larger than the sum of its proper divisors (1).
21151342097 is an equidigital number, since it uses as much as digits as its factorization.
21151342097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 35.
The spelling of 21151342097 in words is "twenty-one billion, one hundred fifty-one million, three hundred forty-two thousand, ninety-seven".
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