Base | Representation |
---|---|
bin | 1001100111100111101100… |
… | …11100100000100011101111 |
3 | 2202220011102211110111100112 |
4 | 10303303312130200203233 |
5 | 10233030412212242111 |
6 | 112553203214250235 |
7 | 4312135666202231 |
oct | 463636634404357 |
9 | 82804384414315 |
10 | 21152553634031 |
11 | 6815825098126 |
12 | 245760b4b697b |
13 | ba58a5bb9681 |
14 | 531b09268251 |
15 | 26a35e49de8b |
hex | 133cf67208ef |
21152553634031 has 2 divisors, whose sum is σ = 21152553634032. Its totient is φ = 21152553634030.
The previous prime is 21152553634027. The next prime is 21152553634073. The reversal of 21152553634031 is 13043635525112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21152553634031 - 22 = 21152553634027 is a prime.
It is a super-2 number, since 2×211525536340312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 21152553634031.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21152553624031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10576276817015 + 10576276817016.
It is an arithmetic number, because the mean of its divisors is an integer number (10576276817016).
Almost surely, 221152553634031 is an apocalyptic number.
21152553634031 is a deficient number, since it is larger than the sum of its proper divisors (1).
21152553634031 is an equidigital number, since it uses as much as digits as its factorization.
21152553634031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324000, while the sum is 41.
The spelling of 21152553634031 in words is "twenty-one trillion, one hundred fifty-two billion, five hundred fifty-three million, six hundred thirty-four thousand, thirty-one".
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