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2115343400411 = 13170116061711
BaseRepresentation
bin11110110010000100010…
…010101011110111011011
321111020001220210200201002
4132302010102223313123
5234124210402303121
64255435250215215
7305554116142253
oct36620422536733
97436056720632
102115343400411
1174612622579a
122a1b7428450b
13124625aa5167
14745515a4963
153a05925ee0b
hex1ec844abddb

2115343400411 has 4 divisors (see below), whose sum is σ = 2115359593824. Its totient is φ = 2115327207000.

The previous prime is 2115343400399. The next prime is 2115343400419. The reversal of 2115343400411 is 1140043435112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2115343400411 - 214 = 2115343384027 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2115343400419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7899155 + ... + 8162556.

It is an arithmetic number, because the mean of its divisors is an integer number (528839898456).

Almost surely, 22115343400411 is an apocalyptic number.

2115343400411 is a deficient number, since it is larger than the sum of its proper divisors (16193413).

2115343400411 is a wasteful number, since it uses less digits than its factorization.

2115343400411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16193412.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 2115343400411 its reverse (1140043435112), we get a palindrome (3255386835523).

The spelling of 2115343400411 in words is "two trillion, one hundred fifteen billion, three hundred forty-three million, four hundred thousand, four hundred eleven".

Divisors: 1 131701 16061711 2115343400411