Base | Representation |
---|---|
bin | 11110110010000100010… |
… | …010101011110111011011 |
3 | 21111020001220210200201002 |
4 | 132302010102223313123 |
5 | 234124210402303121 |
6 | 4255435250215215 |
7 | 305554116142253 |
oct | 36620422536733 |
9 | 7436056720632 |
10 | 2115343400411 |
11 | 74612622579a |
12 | 2a1b7428450b |
13 | 124625aa5167 |
14 | 745515a4963 |
15 | 3a05925ee0b |
hex | 1ec844abddb |
2115343400411 has 4 divisors (see below), whose sum is σ = 2115359593824. Its totient is φ = 2115327207000.
The previous prime is 2115343400399. The next prime is 2115343400419. The reversal of 2115343400411 is 1140043435112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2115343400411 - 214 = 2115343384027 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2115343400419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7899155 + ... + 8162556.
It is an arithmetic number, because the mean of its divisors is an integer number (528839898456).
Almost surely, 22115343400411 is an apocalyptic number.
2115343400411 is a deficient number, since it is larger than the sum of its proper divisors (16193413).
2115343400411 is a wasteful number, since it uses less digits than its factorization.
2115343400411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16193412.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 2115343400411 its reverse (1140043435112), we get a palindrome (3255386835523).
The spelling of 2115343400411 in words is "two trillion, one hundred fifteen billion, three hundred forty-three million, four hundred thousand, four hundred eleven".
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