Base | Representation |
---|---|
bin | 11110110010000111110… |
… | …111011000101110011011 |
3 | 21111020020002121121011212 |
4 | 132302013313120232123 |
5 | 234124321224243422 |
6 | 4255445231213335 |
7 | 305555444551151 |
oct | 36620767305633 |
9 | 7436202547155 |
10 | 2115403352987 |
11 | 746157053a81 |
12 | 2a1b9037724b |
13 | 124635336662 |
14 | 7455952d3d1 |
15 | 3a05e6539e2 |
hex | 1ec87dd8b9b |
2115403352987 has 2 divisors, whose sum is σ = 2115403352988. Its totient is φ = 2115403352986.
The previous prime is 2115403352981. The next prime is 2115403352989. The reversal of 2115403352987 is 7892533045112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2115403352987 - 228 = 2115134917531 is a prime.
Together with 2115403352989, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2115403352981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057701676493 + 1057701676494.
It is an arithmetic number, because the mean of its divisors is an integer number (1057701676494).
Almost surely, 22115403352987 is an apocalyptic number.
2115403352987 is a deficient number, since it is larger than the sum of its proper divisors (1).
2115403352987 is an equidigital number, since it uses as much as digits as its factorization.
2115403352987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1814400, while the sum is 50.
The spelling of 2115403352987 in words is "two trillion, one hundred fifteen billion, four hundred three million, three hundred fifty-two thousand, nine hundred eighty-seven".
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