Base | Representation |
---|---|
bin | 1001100111101010111110… |
… | …10101111000010110000100 |
3 | 2202220022222110222011021122 |
4 | 10303311133111320112010 |
5 | 10233043013224113012 |
6 | 112554054002333112 |
7 | 4312230415640654 |
oct | 463653725702604 |
9 | 82808873864248 |
10 | 21154313504132 |
11 | 6816548532626 |
12 | 2457a2095a198 |
13 | ba5ac6698a23 |
14 | 531c34c96364 |
15 | 26a413c2be72 |
hex | 133d5f578584 |
21154313504132 has 48 divisors (see below), whose sum is σ = 39950776599552. Its totient is φ = 9763840120320.
The previous prime is 21154313504087. The next prime is 21154313504147. The reversal of 21154313504132 is 23140531345112.
It is a super-2 number, since 2×211543135041322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21154313504092 and 21154313504101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9688157 + ... + 11669147.
It is an arithmetic number, because the mean of its divisors is an integer number (832307845824).
Almost surely, 221154313504132 is an apocalyptic number.
It is an amenable number.
21154313504132 is a deficient number, since it is larger than the sum of its proper divisors (18796463095420).
21154313504132 is a wasteful number, since it uses less digits than its factorization.
21154313504132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1984028 (or 1984026 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 21154313504132 its reverse (23140531345112), we get a palindrome (44294844849244).
The spelling of 21154313504132 in words is "twenty-one trillion, one hundred fifty-four billion, three hundred thirteen million, five hundred four thousand, one hundred thirty-two".
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