Base | Representation |
---|---|
bin | 11110110010001010010… |
… | …011110010100101111001 |
3 | 21111020022221202122011201 |
4 | 132302022103302211321 |
5 | 234124412223302101 |
6 | 4255453254054201 |
7 | 305556453213661 |
oct | 36621223624571 |
9 | 7436287678151 |
10 | 2115444353401 |
11 | 746178208215 |
12 | 2a1ba204a361 |
13 | 124640990662 |
14 | 74560b631a1 |
15 | 3a063051e01 |
hex | 1ec8a4f2979 |
2115444353401 has 2 divisors, whose sum is σ = 2115444353402. Its totient is φ = 2115444353400.
The previous prime is 2115444353389. The next prime is 2115444353411. The reversal of 2115444353401 is 1043534445112.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2034945045225 + 80499308176 = 1426515^2 + 283724^2 .
It is a cyclic number.
It is not a de Polignac number, because 2115444353401 - 217 = 2115444222329 is a prime.
It is not a weakly prime, because it can be changed into another prime (2115444353411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057722176700 + 1057722176701.
It is an arithmetic number, because the mean of its divisors is an integer number (1057722176701).
Almost surely, 22115444353401 is an apocalyptic number.
It is an amenable number.
2115444353401 is a deficient number, since it is larger than the sum of its proper divisors (1).
2115444353401 is an equidigital number, since it uses as much as digits as its factorization.
2115444353401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 2115444353401 its reverse (1043534445112), we get a palindrome (3158978798513).
The spelling of 2115444353401 in words is "two trillion, one hundred fifteen billion, four hundred forty-four million, three hundred fifty-three thousand, four hundred one".
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