Base | Representation |
---|---|
bin | 11110110010010000101… |
… | …010101100001111100001 |
3 | 21111020121101110212020112 |
4 | 132302100222230033201 |
5 | 234130122030120001 |
6 | 4255512024221105 |
7 | 305562216653216 |
oct | 36622052541741 |
9 | 7436541425215 |
10 | 2115551020001 |
11 | 746222442431 |
12 | 2a201190a795 |
13 | 124659ac96a3 |
14 | 74570dabb0d |
15 | 3a06c5c1cbb |
hex | 1ec90aac3e1 |
2115551020001 has 2 divisors, whose sum is σ = 2115551020002. Its totient is φ = 2115551020000.
The previous prime is 2115551019997. The next prime is 2115551020027. The reversal of 2115551020001 is 1000201555112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2067786480400 + 47764539601 = 1437980^2 + 218551^2 .
It is a cyclic number.
It is not a de Polignac number, because 2115551020001 - 22 = 2115551019997 is a prime.
It is a super-2 number, since 2×21155510200012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2115551020061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057775510000 + 1057775510001.
It is an arithmetic number, because the mean of its divisors is an integer number (1057775510001).
Almost surely, 22115551020001 is an apocalyptic number.
It is an amenable number.
2115551020001 is a deficient number, since it is larger than the sum of its proper divisors (1).
2115551020001 is an equidigital number, since it uses as much as digits as its factorization.
2115551020001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 500, while the sum is 23.
Adding to 2115551020001 its reverse (1000201555112), we get a palindrome (3115752575113).
The spelling of 2115551020001 in words is "two trillion, one hundred fifteen billion, five hundred fifty-one million, twenty thousand, one".
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