Base | Representation |
---|---|
bin | 1001100111111011101111… |
… | …11110100001100111001111 |
3 | 2202221012012221011021021012 |
4 | 10303331313332201213033 |
5 | 10233214433041343303 |
6 | 113002143221155435 |
7 | 4312666501145405 |
oct | 463756776414717 |
9 | 82835187137235 |
10 | 21163316746703 |
11 | 681a348638a6a |
12 | 2459713b5bb7b |
13 | ba68cca12bb1 |
14 | 53244a8b3475 |
15 | 26a78e3495d8 |
hex | 133f77fa19cf |
21163316746703 has 2 divisors, whose sum is σ = 21163316746704. Its totient is φ = 21163316746702.
The previous prime is 21163316746687. The next prime is 21163316746727. The reversal of 21163316746703 is 30764761336112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21163316746703 - 24 = 21163316746687 is a prime.
It is a super-2 number, since 2×211633167467032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21163316743703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10581658373351 + 10581658373352.
It is an arithmetic number, because the mean of its divisors is an integer number (10581658373352).
Almost surely, 221163316746703 is an apocalyptic number.
21163316746703 is a deficient number, since it is larger than the sum of its proper divisors (1).
21163316746703 is an equidigital number, since it uses as much as digits as its factorization.
21163316746703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2286144, while the sum is 50.
The spelling of 21163316746703 in words is "twenty-one trillion, one hundred sixty-three billion, three hundred sixteen million, seven hundred forty-six thousand, seven hundred three".
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