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211815055584131 is a prime number
BaseRepresentation
bin110000001010010100001001…
…001001010110101110000011
31000202222022200102011101122112
4300022110021021112232003
5210230334213212143011
62030254254310525535
762421063351615356
oct6012241111265603
91022868612141575
10211815055584131
116154429596316a
121b90b2156668ab
1391260c686a65c
143a43c90c9429d
151974be067e58b
hexc0a509256b83

211815055584131 has 2 divisors, whose sum is σ = 211815055584132. Its totient is φ = 211815055584130.

The previous prime is 211815055584109. The next prime is 211815055584163. The reversal of 211815055584131 is 131485550518112.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211815055584131 - 210 = 211815055583107 is a prime.

It is a super-2 number, since 2×2118150555841312 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211815055584131.

It is not a weakly prime, because it can be changed into another prime (211815055584031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105907527792065 + 105907527792066.

It is an arithmetic number, because the mean of its divisors is an integer number (105907527792066).

Almost surely, 2211815055584131 is an apocalyptic number.

211815055584131 is a deficient number, since it is larger than the sum of its proper divisors (1).

211815055584131 is an equidigital number, since it uses as much as digits as its factorization.

211815055584131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960000, while the sum is 50.

The spelling of 211815055584131 in words is "two hundred eleven trillion, eight hundred fifteen billion, fifty-five million, five hundred eighty-four thousand, one hundred thirty-one".