212000102113 has 2 divisors, whose sum is σ = 212000102114. Its totient is φ = 212000102112.

The previous prime is 212000102107. The next prime is 212000102117. The reversal of 212000102113 is 311201000212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 202781797969 + 9218304144 = 450313^2 + 96012^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-212000102113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 212000102093 and 212000102102.

It is not a weakly prime, because it can be changed into another prime (212000102117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106000051056 + 106000051057.

It is an arithmetic number, because the mean of its divisors is an integer number (106000051057).

Almost surely, 2^212000102113 is an apocalyptic number.

It is an amenable number.

212000102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

212000102113 is an equidigital number, since it uses as much as digits as its factorization.

212000102113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 212000102113 its reverse (311201000212), we get a palindrome (523201102325).

The spelling of 212000102113 in words is "two hundred twelve billion, one hundred two thousand, one hundred thirteen".