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212001221012143 is a prime number
BaseRepresentation
bin110000001101000001100001…
…011110000110101010101111
31000210122010012121021000010211
4300031001201132012222233
5210241412000034342033
62030520003314043251
762440403613631303
oct6015014136065257
91023563177230124
10212001221012143
11616062384456a2
121b93b30bb79527
13913a82491bc54
143a4ccb1841d03
15197998929b2cd
hexc0d061786aaf

212001221012143 has 2 divisors, whose sum is σ = 212001221012144. Its totient is φ = 212001221012142.

The previous prime is 212001221012131. The next prime is 212001221012149. The reversal of 212001221012143 is 341210122100212.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212001221012143 is a prime.

It is a super-3 number, since 3×2120012210121433 (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212001221012149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106000610506071 + 106000610506072.

It is an arithmetic number, because the mean of its divisors is an integer number (106000610506072).

Almost surely, 2212001221012143 is an apocalyptic number.

212001221012143 is a deficient number, since it is larger than the sum of its proper divisors (1).

212001221012143 is an equidigital number, since it uses as much as digits as its factorization.

212001221012143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 212001221012143 its reverse (341210122100212), we get a palindrome (553211343112355).

The spelling of 212001221012143 in words is "two hundred twelve trillion, one billion, two hundred twenty-one million, twelve thousand, one hundred forty-three".