Base | Representation |
---|---|
bin | 1100010101110011011… |
… | …1000010111010010111 |
3 | 202021020102201112100210 |
4 | 3011130313002322113 |
5 | 11433144400044343 |
6 | 241221402340503 |
7 | 21213560403246 |
oct | 3053467027227 |
9 | 667212645323 |
10 | 212011331223 |
11 | 81a0596211a |
12 | 3510a1ba733 |
13 | 16cb9920463 |
14 | a39340c95d |
15 | 57acbd2333 |
hex | 315cdc2e97 |
212011331223 has 64 divisors (see below), whose sum is σ = 312236697600. Its totient is φ = 127484098560.
The previous prime is 212011331197. The next prime is 212011331263. The reversal of 212011331223 is 322133110212.
It is not a de Polignac number, because 212011331223 - 213 = 212011323031 is a prime.
It is a super-2 number, since 2×2120113312232 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 212011331223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (212011331263) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 18821413 + ... + 18832673.
It is an arithmetic number, because the mean of its divisors is an integer number (4878698400).
Almost surely, 2212011331223 is an apocalyptic number.
212011331223 is a deficient number, since it is larger than the sum of its proper divisors (100225366377).
212011331223 is a wasteful number, since it uses less digits than its factorization.
212011331223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11512.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 212011331223 its reverse (322133110212), we get a palindrome (534144441435).
The spelling of 212011331223 in words is "two hundred twelve billion, eleven million, three hundred thirty-one thousand, two hundred twenty-three".
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