Base | Representation |
---|---|
bin | 11110110110100001000… |
… | …011110100111100011001 |
3 | 21111200101212201111201012 |
4 | 132312201003310330121 |
5 | 234214001434340433 |
6 | 4301545315103305 |
7 | 306113401155065 |
oct | 36664103647431 |
9 | 7450355644635 |
10 | 2120121011993 |
11 | 748158049016 |
12 | 2a2a882a1b35 |
13 | 124c0783b16a |
14 | 74885cd6aa5 |
15 | 3a2388d8848 |
hex | 1eda10f4f19 |
2120121011993 has 2 divisors, whose sum is σ = 2120121011994. Its totient is φ = 2120121011992.
The previous prime is 2120121011927. The next prime is 2120121012043. The reversal of 2120121011993 is 3991101210212.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2023199001664 + 96922010329 = 1422392^2 + 311323^2 .
It is a cyclic number.
It is not a de Polignac number, because 2120121011993 - 28 = 2120121011737 is a prime.
It is a super-5 number, since 5×21201210119935 (a number of 63 digits) contains 55555 as substring.
It is not a weakly prime, because it can be changed into another prime (2120121011093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060060505996 + 1060060505997.
It is an arithmetic number, because the mean of its divisors is an integer number (1060060505997).
Almost surely, 22120121011993 is an apocalyptic number.
It is an amenable number.
2120121011993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2120121011993 is an equidigital number, since it uses as much as digits as its factorization.
2120121011993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 32.
It can be divided in two parts, 21201210119 and 93, that added together give a palindrome (21201210212).
The spelling of 2120121011993 in words is "two trillion, one hundred twenty billion, one hundred twenty-one million, eleven thousand, nine hundred ninety-three".
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