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212012110021081 is a prime number
BaseRepresentation
bin110000001101001011101010…
…100000011000000111011001
31000210200011022110211222021011
4300031023222200120013121
5210242101300131133311
62030525004015213521
762441240504654116
oct6015135240300731
91023604273758234
10212012110021081
116160a915a65237
121b94144a8172a1
13913b86b8550c6
143a4d625a9d90d
151979dc5214321
hexc0d2ea8181d9

212012110021081 has 2 divisors, whose sum is σ = 212012110021082. Its totient is φ = 212012110021080.

The previous prime is 212012110020989. The next prime is 212012110021213. The reversal of 212012110021081 is 180120011210212.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 198427791873600 + 13584318147481 = 14086440^2 + 3685691^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212012110021081 is a prime.

It is a super-2 number, since 2×2120121100210812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (212012110051081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006055010540 + 106006055010541.

It is an arithmetic number, because the mean of its divisors is an integer number (106006055010541).

Almost surely, 2212012110021081 is an apocalyptic number.

It is an amenable number.

212012110021081 is a deficient number, since it is larger than the sum of its proper divisors (1).

212012110021081 is an equidigital number, since it uses as much as digits as its factorization.

212012110021081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 22.

Adding to 212012110021081 its reverse (180120011210212), we get a palindrome (392132121231293).

The spelling of 212012110021081 in words is "two hundred twelve trillion, twelve billion, one hundred ten million, twenty-one thousand, eighty-one".