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212012121283 is a prime number
BaseRepresentation
bin1100010101110011101…
…0000011110011000011
3202021020111012200010021
43011130322003303003
511433200100340113
6241221431314311
721213600203524
oct3053472036303
9667214180107
10212012121283
1181a06351766
123510a51b997
1316cb9b38c51
14a39357684b
1557accdb48d
hex315ce83cc3

212012121283 has 2 divisors, whose sum is σ = 212012121284. Its totient is φ = 212012121282.

The previous prime is 212012121257. The next prime is 212012121329. The reversal of 212012121283 is 382121210212.

It is a happy number.

212012121283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 212012121283 - 213 = 212012113091 is a prime.

It is not a weakly prime, because it can be changed into another prime (212016121283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006060641 + 106006060642.

It is an arithmetic number, because the mean of its divisors is an integer number (106006060642).

Almost surely, 2212012121283 is an apocalyptic number.

212012121283 is a deficient number, since it is larger than the sum of its proper divisors (1).

212012121283 is an equidigital number, since it uses as much as digits as its factorization.

212012121283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 212012121283 its reverse (382121210212), we get a palindrome (594133331495).

The spelling of 212012121283 in words is "two hundred twelve billion, twelve million, one hundred twenty-one thousand, two hundred eighty-three".