212012200120121 has 4 divisors (see below), whose sum is σ = 212013991744512. Its totient is φ = 212010408495732.

The previous prime is 212012200120099. The next prime is 212012200120181. The reversal of 212012200120121 is 121021002210212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-212012200120121 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 212012200120121.

It is not an unprimeable number, because it can be changed into a prime (212012200120181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 895634681 + ... + 895871366.

It is an arithmetic number, because the mean of its divisors is an integer number (53003497936128).

Almost surely, 2^{212012200120121} is an apocalyptic number.

It is an amenable number.

212012200120121 is a deficient number, since it is larger than the sum of its proper divisors (1791624391).

212012200120121 is a wasteful number, since it uses less digits than its factorization.

212012200120121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1791624390.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 212012200120121 its reverse (121021002210212), we get a palindrome (333033202330333).

The spelling of 212012200120121 in words is "two hundred twelve trillion, twelve billion, two hundred million, one hundred twenty thousand, one hundred twenty-one".