Base | Representation |
---|---|
bin | 1100010101110011101… |
… | …0010111000101101111 |
3 | 202021020111100200111221 |
4 | 3011130322113011233 |
5 | 11433200110402203 |
6 | 241221433124211 |
7 | 21213600653101 |
oct | 3053472270557 |
9 | 667214320457 |
10 | 212012200303 |
11 | 81a063a6072 |
12 | 3510a559667 |
13 | 16cb9b65bc7 |
14 | a393597571 |
15 | 57acd04abd |
hex | 315ce9716f |
212012200303 has 2 divisors, whose sum is σ = 212012200304. Its totient is φ = 212012200302.
The previous prime is 212012200291. The next prime is 212012200349. The reversal of 212012200303 is 303002210212.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212012200303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212012200373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006100151 + 106006100152.
It is an arithmetic number, because the mean of its divisors is an integer number (106006100152).
Almost surely, 2212012200303 is an apocalyptic number.
212012200303 is a deficient number, since it is larger than the sum of its proper divisors (1).
212012200303 is an equidigital number, since it uses as much as digits as its factorization.
212012200303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 212012200303 its reverse (303002210212), we get a palindrome (515014410515).
Subtracting 212012200303 from its reverse (303002210212), we obtain a palindrome (90990009909).
The spelling of 212012200303 in words is "two hundred twelve billion, twelve million, two hundred thousand, three hundred three".
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