Base | Representation |
---|---|
bin | 1100010101110011101… |
… | …0010111010110000111 |
3 | 202021020111100201221202 |
4 | 3011130322113112013 |
5 | 11433200110420401 |
6 | 241221433133115 |
7 | 21213600656126 |
oct | 3053472272607 |
9 | 667214321852 |
10 | 212012201351 |
11 | 81a063a6935 |
12 | 3510a55a19b |
13 | 16cb9b66522 |
14 | a393597abd |
15 | 57acd0506b |
hex | 315ce97587 |
212012201351 has 2 divisors, whose sum is σ = 212012201352. Its totient is φ = 212012201350.
The previous prime is 212012201311. The next prime is 212012201411. The reversal of 212012201351 is 153102210212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212012201351 - 222 = 212008007047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212012201311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006100675 + 106006100676.
It is an arithmetic number, because the mean of its divisors is an integer number (106006100676).
Almost surely, 2212012201351 is an apocalyptic number.
212012201351 is a deficient number, since it is larger than the sum of its proper divisors (1).
212012201351 is an equidigital number, since it uses as much as digits as its factorization.
212012201351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 212012201351 its reverse (153102210212), we get a palindrome (365114411563).
The spelling of 212012201351 in words is "two hundred twelve billion, twelve million, two hundred one thousand, three hundred fifty-one".
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