Base | Representation |
---|---|
bin | 1100010101110011101… |
… | …0010111100000111001 |
3 | 202021020111100202220022 |
4 | 3011130322113200321 |
5 | 11433200110431131 |
6 | 241221433140225 |
7 | 21213600661133 |
oct | 3053472274071 |
9 | 667214322808 |
10 | 212012202041 |
11 | 81a063a7402 |
12 | 3510a55a675 |
13 | 16cb9b66933 |
14 | a393598053 |
15 | 57acd0537b |
hex | 315ce97839 |
212012202041 has 2 divisors, whose sum is σ = 212012202042. Its totient is φ = 212012202040.
The previous prime is 212012201923. The next prime is 212012202091. The reversal of 212012202041 is 140202210212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 115413075625 + 96599126416 = 339725^2 + 310804^2 .
It is a cyclic number.
It is not a de Polignac number, because 212012202041 - 222 = 212008007737 is a prime.
It is a super-3 number, since 3×2120122020413 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (212012202091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006101020 + 106006101021.
It is an arithmetic number, because the mean of its divisors is an integer number (106006101021).
Almost surely, 2212012202041 is an apocalyptic number.
It is an amenable number.
212012202041 is a deficient number, since it is larger than the sum of its proper divisors (1).
212012202041 is an equidigital number, since it uses as much as digits as its factorization.
212012202041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 17.
Adding to 212012202041 its reverse (140202210212), we get a palindrome (352214412253).
The spelling of 212012202041 in words is "two hundred twelve billion, twelve million, two hundred two thousand, forty-one".
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