Base | Representation |
---|---|
bin | 10011101111101100… |
… | …100011000111111011 |
3 | 2000201112222201210211 |
4 | 103233230203013323 |
5 | 321410013131021 |
6 | 13423441251551 |
7 | 1350250044061 |
oct | 235754430773 |
9 | 60645881724 |
10 | 21201302011 |
11 | 8a9a644aaa |
12 | 4138333bb7 |
13 | 1ccb536926 |
14 | 1051a74031 |
15 | 8414623e1 |
hex | 4efb231fb |
21201302011 has 4 divisors (see below), whose sum is σ = 21202951752. Its totient is φ = 21199652272.
The previous prime is 21201301999. The next prime is 21201302027. The reversal of 21201302011 is 11020310212.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21201302011 - 223 = 21192913403 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21201301982 and 21201302000.
It is not an unprimeable number, because it can be changed into a prime (21201302041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 805441 + ... + 831346.
It is an arithmetic number, because the mean of its divisors is an integer number (5300737938).
Almost surely, 221201302011 is an apocalyptic number.
21201302011 is a deficient number, since it is larger than the sum of its proper divisors (1649741).
21201302011 is a wasteful number, since it uses less digits than its factorization.
21201302011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1649740.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 21201302011 its reverse (11020310212), we get a palindrome (32221612223).
The spelling of 21201302011 in words is "twenty-one billion, two hundred one million, three hundred two thousand, eleven".
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