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212013100031 is a prime number
BaseRepresentation
bin1100010101110011110…
…1110010101111111111
3202021020120001101201012
43011130331302233333
511433200323200111
6241221504305435
721213611421155
oct3053475625777
9667216041635
10212013100031
1181a06960047
123510a91227b
1316cba0bc5a5
14a39374d3d5
1557ace3148b
hex315cf72bff

212013100031 has 2 divisors, whose sum is σ = 212013100032. Its totient is φ = 212013100030.

The previous prime is 212013100003. The next prime is 212013100109. The reversal of 212013100031 is 130001310212.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212013100031 is a prime.

It is a super-2 number, since 2×2120131000312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 212013099979 and 212013100015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212013100231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006550015 + 106006550016.

It is an arithmetic number, because the mean of its divisors is an integer number (106006550016).

Almost surely, 2212013100031 is an apocalyptic number.

212013100031 is a deficient number, since it is larger than the sum of its proper divisors (1).

212013100031 is an equidigital number, since it uses as much as digits as its factorization.

212013100031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 212013100031 its reverse (130001310212), we get a palindrome (342014410243).

The spelling of 212013100031 in words is "two hundred twelve billion, thirteen million, one hundred thousand, thirty-one".