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2120131452555 = 32547114032279
BaseRepresentation
bin11110110110100001101…
…011101001111010001011
321111200102121100221110200
4132312201223221322023
5234214012122440210
64301550330543243
7306113556001044
oct36664153517213
97450377327420
102120131452555
11748162a2a186
122a2a8b897b23
13124c09a553cc
14748874538cb
153a23979c0c0
hex1eda1ae9e8b

2120131452555 has 12 divisors (see below), whose sum is σ = 3674894517840. Its totient is φ = 1130736774672.

The previous prime is 2120131452529. The next prime is 2120131452563. The reversal of 2120131452555 is 5552541310212.

2120131452555 is a `hidden beast` number, since 2 + 1 + 20 + 1 + 31 + 4 + 52 + 555 = 666.

It is not a de Polignac number, because 2120131452555 - 212 = 2120131448459 is a prime.

It is a super-2 number, since 2×21201314525552 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23557016095 + ... + 23557016184.

It is an arithmetic number, because the mean of its divisors is an integer number (306241209820).

Almost surely, 22120131452555 is an apocalyptic number.

2120131452555 is a deficient number, since it is larger than the sum of its proper divisors (1554763065285).

2120131452555 is a wasteful number, since it uses less digits than its factorization.

2120131452555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47114032290 (or 47114032287 counting only the distinct ones).

The product of its (nonzero) digits is 60000, while the sum is 36.

Adding to 2120131452555 its reverse (5552541310212), we get a palindrome (7672672762767).

The spelling of 2120131452555 in words is "two trillion, one hundred twenty billion, one hundred thirty-one million, four hundred fifty-two thousand, five hundred fifty-five".

Divisors: 1 3 5 9 15 45 47114032279 141342096837 235570161395 424026290511 706710484185 2120131452555