Base | Representation |
---|---|
bin | 11110110110100001101… |
… | …011101001111010001011 |
3 | 21111200102121100221110200 |
4 | 132312201223221322023 |
5 | 234214012122440210 |
6 | 4301550330543243 |
7 | 306113556001044 |
oct | 36664153517213 |
9 | 7450377327420 |
10 | 2120131452555 |
11 | 748162a2a186 |
12 | 2a2a8b897b23 |
13 | 124c09a553cc |
14 | 748874538cb |
15 | 3a23979c0c0 |
hex | 1eda1ae9e8b |
2120131452555 has 12 divisors (see below), whose sum is σ = 3674894517840. Its totient is φ = 1130736774672.
The previous prime is 2120131452529. The next prime is 2120131452563. The reversal of 2120131452555 is 5552541310212.
2120131452555 is a `hidden beast` number, since 2 + 1 + 20 + 1 + 31 + 4 + 52 + 555 = 666.
It is not a de Polignac number, because 2120131452555 - 212 = 2120131448459 is a prime.
It is a super-2 number, since 2×21201314525552 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23557016095 + ... + 23557016184.
It is an arithmetic number, because the mean of its divisors is an integer number (306241209820).
Almost surely, 22120131452555 is an apocalyptic number.
2120131452555 is a deficient number, since it is larger than the sum of its proper divisors (1554763065285).
2120131452555 is a wasteful number, since it uses less digits than its factorization.
2120131452555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47114032290 (or 47114032287 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 36.
Adding to 2120131452555 its reverse (5552541310212), we get a palindrome (7672672762767).
The spelling of 2120131452555 in words is "two trillion, one hundred twenty billion, one hundred thirty-one million, four hundred fifty-two thousand, five hundred fifty-five".
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