Base | Representation |
---|---|
bin | 1100010101110011111… |
… | …0100011011100101101 |
3 | 202021020120102112022222 |
4 | 3011130332203130231 |
5 | 11433200401041001 |
6 | 241221512445125 |
7 | 21213613211543 |
oct | 3053476433455 |
9 | 667216375288 |
10 | 212013299501 |
11 | 81a06a869a3 |
12 | 3510a9a97a5 |
13 | 16cba15c313 |
14 | a3937a1d93 |
15 | 57ace7061b |
hex | 315cfa372d |
212013299501 has 2 divisors, whose sum is σ = 212013299502. Its totient is φ = 212013299500.
The previous prime is 212013299497. The next prime is 212013299513. The reversal of 212013299501 is 105992310212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 190489475401 + 21523824100 = 436451^2 + 146710^2 .
It is a cyclic number.
It is not a de Polignac number, because 212013299501 - 22 = 212013299497 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212013299101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006649750 + 106006649751.
It is an arithmetic number, because the mean of its divisors is an integer number (106006649751).
Almost surely, 2212013299501 is an apocalyptic number.
It is an amenable number.
212013299501 is a deficient number, since it is larger than the sum of its proper divisors (1).
212013299501 is an equidigital number, since it uses as much as digits as its factorization.
212013299501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 35.
The spelling of 212013299501 in words is "two hundred twelve billion, thirteen million, two hundred ninety-nine thousand, five hundred one".
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