Base | Representation |
---|---|
bin | 1100010101110011111… |
… | …1000010001100000101 |
3 | 202021020120122221001101 |
4 | 3011130333002030011 |
5 | 11433200414103123 |
6 | 241221515300101 |
7 | 21213614244616 |
oct | 3053477021405 |
9 | 667216587041 |
10 | 212013425413 |
11 | 81a07062559 |
12 | 3510aa4a631 |
13 | 16cba1a471a |
14 | a3937d5c0d |
15 | 57ace97aad |
hex | 315cfc2305 |
212013425413 has 4 divisors (see below), whose sum is σ = 214071808288. Its totient is φ = 209955042540.
The previous prime is 212013425401. The next prime is 212013425431. The reversal of 212013425413 is 314524310212.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 212013425413 - 25 = 212013425381 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (212013428413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1029191283 + ... + 1029191488.
It is an arithmetic number, because the mean of its divisors is an integer number (53517952072).
Almost surely, 2212013425413 is an apocalyptic number.
It is an amenable number.
212013425413 is a deficient number, since it is larger than the sum of its proper divisors (2058382875).
212013425413 is a wasteful number, since it uses less digits than its factorization.
212013425413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2058382874.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 212013425413 its reverse (314524310212), we get a palindrome (526537735625).
The spelling of 212013425413 in words is "two hundred twelve billion, thirteen million, four hundred twenty-five thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •