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21201485401 is a prime number
BaseRepresentation
bin10011101111101101…
…001111111001011001
32000201120100001101001
4103233231033321121
5321410040013101
613423445225001
71350251436535
oct235755177131
960646301331
1021201485401
118a9a75a868
124138402161
131ccb59c245
141051ac0bc5
1584149b901
hex4efb4fe59

21201485401 has 2 divisors, whose sum is σ = 21201485402. Its totient is φ = 21201485400.

The previous prime is 21201485381. The next prime is 21201485413. The reversal of 21201485401 is 10458410212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21097853001 + 103632400 = 145251^2 + 10180^2 .

It is a cyclic number.

It is not a de Polignac number, because 21201485401 - 227 = 21067267673 is a prime.

It is a super-2 number, since 2×212014854012 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21201485401.

It is not a weakly prime, because it can be changed into another prime (21201465401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600742700 + 10600742701.

It is an arithmetic number, because the mean of its divisors is an integer number (10600742701).

Almost surely, 221201485401 is an apocalyptic number.

It is an amenable number.

21201485401 is a deficient number, since it is larger than the sum of its proper divisors (1).

21201485401 is an equidigital number, since it uses as much as digits as its factorization.

21201485401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2560, while the sum is 28.

Adding to 21201485401 its reverse (10458410212), we get a palindrome (31659895613).

The spelling of 21201485401 in words is "twenty-one billion, two hundred one million, four hundred eighty-five thousand, four hundred one".