Search a number
-
+
2120150010001 = 6134756557541
BaseRepresentation
bin11110110110100010110…
…010011100100010010001
321111200110220021202111111
4132312202302130202101
5234214031400310001
64301552232413321
7306114202511302
oct36664262344221
97450426252444
102120150010001
11748172454711
122a2a95b47241
13124c1085204a
1474889ac47a9
153a23b215851
hex1eda2c9c891

2120150010001 has 4 divisors (see below), whose sum is σ = 2154906567604. Its totient is φ = 2085393452400.

The previous prime is 2120150009983. The next prime is 2120150010031. The reversal of 2120150010001 is 1000100510212.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1204681856400 + 915468153601 = 1097580^2 + 956801^2 .

It is a cyclic number.

It is not a de Polignac number, because 2120150010001 - 25 = 2120150009969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2120150010031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17378278710 + ... + 17378278831.

It is an arithmetic number, because the mean of its divisors is an integer number (538726641901).

Almost surely, 22120150010001 is an apocalyptic number.

It is an amenable number.

2120150010001 is a deficient number, since it is larger than the sum of its proper divisors (34756557603).

2120150010001 is an equidigital number, since it uses as much as digits as its factorization.

2120150010001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34756557602.

The product of its (nonzero) digits is 20, while the sum is 13.

Adding to 2120150010001 its reverse (1000100510212), we get a palindrome (3120250520213).

The spelling of 2120150010001 in words is "two trillion, one hundred twenty billion, one hundred fifty million, ten thousand, one".

Divisors: 1 61 34756557541 2120150010001