Base | Representation |
---|---|
bin | 1100010101110101100… |
… | …1100001111010111011 |
3 | 202021021001201210210012 |
4 | 3011131121201322323 |
5 | 11433204203334011 |
6 | 241222324212135 |
7 | 21214030263542 |
oct | 3053531417273 |
9 | 667231653705 |
10 | 212020371131 |
11 | 81a0aa76a18 |
12 | 3511123a04b |
13 | 16cbb76700a |
14 | a3946c3159 |
15 | 57ad8baa8b |
hex | 315d661ebb |
212020371131 has 2 divisors, whose sum is σ = 212020371132. Its totient is φ = 212020371130.
The previous prime is 212020371127. The next prime is 212020371179. The reversal of 212020371131 is 131173020212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212020371131 - 22 = 212020371127 is a prime.
It is a super-2 number, since 2×2120203711312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 212020371097 and 212020371106.
It is not a weakly prime, because it can be changed into another prime (212020301131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106010185565 + 106010185566.
It is an arithmetic number, because the mean of its divisors is an integer number (106010185566).
Almost surely, 2212020371131 is an apocalyptic number.
212020371131 is a deficient number, since it is larger than the sum of its proper divisors (1).
212020371131 is an equidigital number, since it uses as much as digits as its factorization.
212020371131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 212020371131 its reverse (131173020212), we get a palindrome (343193391343).
The spelling of 212020371131 in words is "two hundred twelve billion, twenty million, three hundred seventy-one thousand, one hundred thirty-one".
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