Base | Representation |
---|---|
bin | 1001101001000100000000… |
… | …01111011011011010001011 |
3 | 2210001220100111200212012221 |
4 | 10310202000033123122023 |
5 | 10234333410141214011 |
6 | 113032040453314511 |
7 | 4315542024212161 |
oct | 464420017333213 |
9 | 83056314625187 |
10 | 21202110101131 |
11 | 6834845461363 |
12 | 246513b935a37 |
13 | baa472ab519b |
14 | 53428ab01231 |
15 | 26b7aee31971 |
hex | 1348803db68b |
21202110101131 has 2 divisors, whose sum is σ = 21202110101132. Its totient is φ = 21202110101130.
The previous prime is 21202110101113. The next prime is 21202110101231. The reversal of 21202110101131 is 13110101120212.
It is a happy number.
Together with previous prime (21202110101113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21202110101131 - 213 = 21202110092939 is a prime.
It is a super-2 number, since 2×212021101011312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21202110101231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10601055050565 + 10601055050566.
It is an arithmetic number, because the mean of its divisors is an integer number (10601055050566).
Almost surely, 221202110101131 is an apocalyptic number.
21202110101131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21202110101131 is an equidigital number, since it uses as much as digits as its factorization.
21202110101131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 21202110101131 its reverse (13110101120212), we get a palindrome (34312211221343).
The spelling of 21202110101131 in words is "twenty-one trillion, two hundred two billion, one hundred ten million, one hundred one thousand, one hundred thirty-one".
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