Base | Representation |
---|---|
bin | 1001101001000100000000… |
… | …10111011011111000010011 |
3 | 2210001220100122122111121122 |
4 | 10310202000113123320103 |
5 | 10234333411210401321 |
6 | 113032041010312455 |
7 | 4315542051104015 |
oct | 464420027337023 |
9 | 83056318574548 |
10 | 21202112200211 |
11 | 6834846665438 |
12 | 246514058872b |
13 | baa47336b747 |
14 | 53428b0ca1b5 |
15 | 26b7b01e88ab |
hex | 1348805dbe13 |
21202112200211 has 2 divisors, whose sum is σ = 21202112200212. Its totient is φ = 21202112200210.
The previous prime is 21202112200201. The next prime is 21202112200219. The reversal of 21202112200211 is 11200221120212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21202112200211 - 222 = 21202108005907 is a prime.
It is a super-3 number, since 3×212021122002113 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 21202112200211.
It is not a weakly prime, because it can be changed into another prime (21202112200219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10601056100105 + 10601056100106.
It is an arithmetic number, because the mean of its divisors is an integer number (10601056100106).
Almost surely, 221202112200211 is an apocalyptic number.
21202112200211 is a deficient number, since it is larger than the sum of its proper divisors (1).
21202112200211 is an equidigital number, since it uses as much as digits as its factorization.
21202112200211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 21202112200211 its reverse (11200221120212), we get a palindrome (32402333320423).
The spelling of 21202112200211 in words is "twenty-one trillion, two hundred two billion, one hundred twelve million, two hundred thousand, two hundred eleven".
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