Base | Representation |
---|---|
bin | 1001101001000100001100… |
… | …10100111001111000001111 |
3 | 2210001220121121211000110201 |
4 | 10310202012110321320033 |
5 | 10234334112310344301 |
6 | 113032054541514331 |
7 | 4315544404065316 |
oct | 464420624717017 |
9 | 83056547730421 |
10 | 21202212199951 |
11 | 6834898056752 |
12 | 2465169b729a7 |
13 | baa48acb20a3 |
14 | 53429a4bb27d |
15 | 26b7b8d9d201 |
hex | 134886539e0f |
21202212199951 has 2 divisors, whose sum is σ = 21202212199952. Its totient is φ = 21202212199950.
The previous prime is 21202212199939. The next prime is 21202212200003. The reversal of 21202212199951 is 15999121220212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21202212199951 - 217 = 21202212068879 is a prime.
It is a super-3 number, since 3×212022121999513 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21202212193951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10601106099975 + 10601106099976.
It is an arithmetic number, because the mean of its divisors is an integer number (10601106099976).
Almost surely, 221202212199951 is an apocalyptic number.
21202212199951 is a deficient number, since it is larger than the sum of its proper divisors (1).
21202212199951 is an equidigital number, since it uses as much as digits as its factorization.
21202212199951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 116640, while the sum is 46.
The spelling of 21202212199951 in words is "twenty-one trillion, two hundred two billion, two hundred twelve million, one hundred ninety-nine thousand, nine hundred fifty-one".
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