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212030215121 is a prime number
BaseRepresentation
bin1100010101110111111…
…1000101001111010001
3202021021202020221012102
43011131333011033101
511433214213340441
6241223315210145
721214210043324
oct3053577051721
9667252227172
10212030215121
1181a1558a94a
12351145a6955
1316cc080286a
14a395b267bb
1557ae6b269b
hex315dfc53d1

212030215121 has 2 divisors, whose sum is σ = 212030215122. Its totient is φ = 212030215120.

The previous prime is 212030215093. The next prime is 212030215123. The reversal of 212030215121 is 121512030212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 206865780625 + 5164434496 = 454825^2 + 71864^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212030215121 is a prime.

Together with 212030215123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 212030215093 and 212030215102.

It is not a weakly prime, because it can be changed into another prime (212030215123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106015107560 + 106015107561.

It is an arithmetic number, because the mean of its divisors is an integer number (106015107561).

Almost surely, 2212030215121 is an apocalyptic number.

It is an amenable number.

212030215121 is a deficient number, since it is larger than the sum of its proper divisors (1).

212030215121 is an equidigital number, since it uses as much as digits as its factorization.

212030215121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 212030215121 its reverse (121512030212), we get a palindrome (333542245333).

The spelling of 212030215121 in words is "two hundred twelve billion, thirty million, two hundred fifteen thousand, one hundred twenty-one".