Base | Representation |
---|---|
bin | 110000001101011100100110… |
… | …110101010100011010110011 |
3 | 1000210201220021022021220211121 |
4 | 300031130212311110122303 |
5 | 210242401024303404412 |
6 | 2030541213120523111 |
7 | 62442453354231544 |
oct | 6015344665243263 |
9 | 1023656238256747 |
10 | 212030302013107 |
11 | 61617600960096 |
12 | 1b944a87180497 |
13 | 91404aa797a26 |
14 | 3a5046dbc64cb |
15 | 197a5dc394107 |
hex | c0d726d546b3 |
212030302013107 has 2 divisors, whose sum is σ = 212030302013108. Its totient is φ = 212030302013106.
The previous prime is 212030302013059. The next prime is 212030302013129. The reversal of 212030302013107 is 701310203030212.
It is a happy number.
212030302013107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212030302013107 - 215 = 212030301980339 is a prime.
It is not a weakly prime, because it can be changed into another prime (212030302013137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106015151006553 + 106015151006554.
It is an arithmetic number, because the mean of its divisors is an integer number (106015151006554).
Almost surely, 2212030302013107 is an apocalyptic number.
212030302013107 is a deficient number, since it is larger than the sum of its proper divisors (1).
212030302013107 is an equidigital number, since it uses as much as digits as its factorization.
212030302013107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 212030302013107 its reverse (701310203030212), we get a palindrome (913340505043319).
The spelling of 212030302013107 in words is "two hundred twelve trillion, thirty billion, three hundred two million, thirteen thousand, one hundred seven".
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