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2120313122149 is a prime number
BaseRepresentation
bin11110110110101100100…
…000101010110101100101
321111200220021012201022011
4132312230200222311211
5234214400124402044
64302020340434221
7306121223112025
oct36665440526545
97450807181264
102120313122149
11748246532242
122a2b206a8971
13124c38592201
14748a3623a85
153a24a6d5134
hex1edac82ad65

2120313122149 has 2 divisors, whose sum is σ = 2120313122150. Its totient is φ = 2120313122148.

The previous prime is 2120313122089. The next prime is 2120313122227. The reversal of 2120313122149 is 9412213130212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2103167052900 + 17146069249 = 1450230^2 + 130943^2 .

It is a cyclic number.

It is not a de Polignac number, because 2120313122149 - 27 = 2120313122021 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2120313122149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2120313126149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060156561074 + 1060156561075.

It is an arithmetic number, because the mean of its divisors is an integer number (1060156561075).

Almost surely, 22120313122149 is an apocalyptic number.

It is an amenable number.

2120313122149 is a deficient number, since it is larger than the sum of its proper divisors (1).

2120313122149 is an equidigital number, since it uses as much as digits as its factorization.

2120313122149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 31.

The spelling of 2120313122149 in words is "two trillion, one hundred twenty billion, three hundred thirteen million, one hundred twenty-two thousand, one hundred forty-nine".