Base | Representation |
---|---|
bin | 1100010101111000101… |
… | …0100000101110101011 |
3 | 202021021221220011012021 |
4 | 3011132022200232223 |
5 | 11433221000230212 |
6 | 241223503325311 |
7 | 21214244362501 |
oct | 3053612405653 |
9 | 667257804167 |
10 | 212033211307 |
11 | 81a17246a35 |
12 | 351155b0837 |
13 | 16cc1311558 |
14 | a3962a6671 |
15 | 57aeaa5307 |
hex | 315e2a0bab |
212033211307 has 2 divisors, whose sum is σ = 212033211308. Its totient is φ = 212033211306.
The previous prime is 212033211293. The next prime is 212033211323. The reversal of 212033211307 is 703112330212.
It is a happy number.
212033211307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212033211307 - 27 = 212033211179 is a prime.
It is not a weakly prime, because it can be changed into another prime (212033214307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106016605653 + 106016605654.
It is an arithmetic number, because the mean of its divisors is an integer number (106016605654).
Almost surely, 2212033211307 is an apocalyptic number.
212033211307 is a deficient number, since it is larger than the sum of its proper divisors (1).
212033211307 is an equidigital number, since it uses as much as digits as its factorization.
212033211307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 212033211307 its reverse (703112330212), we get a palindrome (915145541519).
The spelling of 212033211307 in words is "two hundred twelve billion, thirty-three million, two hundred eleven thousand, three hundred seven".
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