Base | Representation |
---|---|
bin | 1001101001010010101110… |
… | …00111001100100000110111 |
3 | 2210002122202001202220020101 |
4 | 10310221113013030200313 |
5 | 10240001100030333303 |
6 | 113035424420014531 |
7 | 4316241551305342 |
oct | 464512707144067 |
9 | 83078661686211 |
10 | 21210010011703 |
11 | 6838129787077 |
12 | 2466785531447 |
13 | bab131682b96 |
14 | 5347d9d93459 |
15 | 26bac375ad1d |
hex | 134a571cc837 |
21210010011703 has 2 divisors, whose sum is σ = 21210010011704. Its totient is φ = 21210010011702.
The previous prime is 21210010011691. The next prime is 21210010011713. The reversal of 21210010011703 is 30711001001212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21210010011703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21210010011713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10605005005851 + 10605005005852.
It is an arithmetic number, because the mean of its divisors is an integer number (10605005005852).
Almost surely, 221210010011703 is an apocalyptic number.
21210010011703 is a deficient number, since it is larger than the sum of its proper divisors (1).
21210010011703 is an equidigital number, since it uses as much as digits as its factorization.
21210010011703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 21210010011703 its reverse (30711001001212), we get a palindrome (51921011012915).
The spelling of 21210010011703 in words is "twenty-one trillion, two hundred ten billion, ten million, eleven thousand, seven hundred three".
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