Base | Representation |
---|---|
bin | 110000001110011110100011… |
… | …111111000100111101101111 |
3 | 1000210222200001211002100211212 |
4 | 300032132203333010331233 |
5 | 210300031044011344413 |
6 | 2031033524313505035 |
7 | 62450541336336251 |
oct | 6016364377047557 |
9 | 1023880054070755 |
10 | 212101121199983 |
11 | 616446424a8404 |
12 | 1b95675041217b |
13 | 9147085852532 |
14 | 3a53a6b51dcd1 |
15 | 197c38486bca8 |
hex | c0e7a3fc4f6f |
212101121199983 has 2 divisors, whose sum is σ = 212101121199984. Its totient is φ = 212101121199982.
The previous prime is 212101121199971. The next prime is 212101121199991. The reversal of 212101121199983 is 389991121101212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212101121199983 - 24 = 212101121199967 is a prime.
It is a super-2 number, since 2×2121011211999832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212101121199683) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106050560599991 + 106050560599992.
It is an arithmetic number, because the mean of its divisors is an integer number (106050560599992).
Almost surely, 2212101121199983 is an apocalyptic number.
212101121199983 is a deficient number, since it is larger than the sum of its proper divisors (1).
212101121199983 is an equidigital number, since it uses as much as digits as its factorization.
212101121199983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 50.
The spelling of 212101121199983 in words is "two hundred twelve trillion, one hundred one billion, one hundred twenty-one million, one hundred ninety-nine thousand, nine hundred eighty-three".
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