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21210120131 is a prime number
BaseRepresentation
bin10011110000001110…
…001011111111000011
32000202011120201222212
4103300032023333003
5321414242321011
613424354252335
71350415021634
oct236016137703
960664521885
1021210120131
118aa4618202
12413b2870ab
132000303555
141052ccb88b
1584210508b
hex4f038bfc3

21210120131 has 2 divisors, whose sum is σ = 21210120132. Its totient is φ = 21210120130.

The previous prime is 21210120103. The next prime is 21210120133. The reversal of 21210120131 is 13102101212.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21210120131 - 222 = 21205925827 is a prime.

It is a super-2 number, since 2×212101201312 (a number of 21 digits) contains 22 as substring.

Together with 21210120133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21210120133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10605060065 + 10605060066.

It is an arithmetic number, because the mean of its divisors is an integer number (10605060066).

Almost surely, 221210120131 is an apocalyptic number.

21210120131 is a deficient number, since it is larger than the sum of its proper divisors (1).

21210120131 is an equidigital number, since it uses as much as digits as its factorization.

21210120131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 21210120131 its reverse (13102101212), we get a palindrome (34312221343).

It can be divided in two parts, 212101 and 20131, that added together give a palindrome (232232).

The spelling of 21210120131 in words is "twenty-one billion, two hundred ten million, one hundred twenty thousand, one hundred thirty-one".