Search a number
-
+
212110000133 = 350596050087
BaseRepresentation
bin1100010110001010111…
…1011100000000000101
3202021111022101102122212
43011202233130000011
511433400130001013
6241235245233205
721216166152563
oct3054257340005
9667438342585
10212110000133
1181a56624579
1235137262805
13170041b9125
14a3a2574a33
1557b66c26a8
hex3162bdc005

212110000133 has 4 divisors (see below), whose sum is σ = 212116085280. Its totient is φ = 212103914988.

The previous prime is 212110000121. The next prime is 212110000153. The reversal of 212110000133 is 331000011212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 212110000133 - 218 = 212109737989 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212110000103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2989985 + ... + 3060102.

It is an arithmetic number, because the mean of its divisors is an integer number (53029021320).

Almost surely, 2212110000133 is an apocalyptic number.

It is an amenable number.

212110000133 is a deficient number, since it is larger than the sum of its proper divisors (6085147).

212110000133 is an equidigital number, since it uses as much as digits as its factorization.

212110000133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6085146.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 212110000133 its reverse (331000011212), we get a palindrome (543110011345).

The spelling of 212110000133 in words is "two hundred twelve billion, one hundred ten million, one hundred thirty-three", and thus it is an aban number.

Divisors: 1 35059 6050087 212110000133