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21211054753 = 73030150679
BaseRepresentation
bin10011110000010001…
…110000001010100001
32000202020100020001111
4103300101300022201
5321420012223003
613424430303321
71350425663530
oct236021601241
960666306044
1021211054753
118aa50a6419
12413b657b41
13200056ca95
141053092317
1584223be6d
hex4f04702a1

21211054753 has 4 divisors (see below), whose sum is σ = 24241205440. Its totient is φ = 18180904068.

The previous prime is 21211054747. The next prime is 21211054783. The reversal of 21211054753 is 35745011212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21211054753 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21211054723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1515075333 + ... + 1515075346.

It is an arithmetic number, because the mean of its divisors is an integer number (6060301360).

Almost surely, 221211054753 is an apocalyptic number.

It is an amenable number.

21211054753 is a deficient number, since it is larger than the sum of its proper divisors (3030150687).

21211054753 is an equidigital number, since it uses as much as digits as its factorization.

21211054753 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3030150686.

The product of its (nonzero) digits is 8400, while the sum is 31.

Adding to 21211054753 its reverse (35745011212), we get a palindrome (56956065965).

The spelling of 21211054753 in words is "twenty-one billion, two hundred eleven million, fifty-four thousand, seven hundred fifty-three".

Divisors: 1 7 3030150679 21211054753