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21211200120133 is a prime number
BaseRepresentation
bin1001101001010100111100…
…00011000110010101000101
32210002202211000011200002101
410310222132003012111011
510240011014212321013
6113040142452112101
74316313212125252
oct464523603062505
983082730150071
1021211200120133
11683868a547161
122466a58005631
13bab2910c2c5a
145348b006a429
1526bb42e908dd
hex134a9e0c6545

21211200120133 has 2 divisors, whose sum is σ = 21211200120134. Its totient is φ = 21211200120132.

The previous prime is 21211200120119. The next prime is 21211200120211. The reversal of 21211200120133 is 33102100211212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19526518129924 + 1684681990209 = 4418882^2 + 1297953^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21211200120133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21211200120133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21211200123133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10605600060066 + 10605600060067.

It is an arithmetic number, because the mean of its divisors is an integer number (10605600060067).

Almost surely, 221211200120133 is an apocalyptic number.

It is an amenable number.

21211200120133 is a deficient number, since it is larger than the sum of its proper divisors (1).

21211200120133 is an equidigital number, since it uses as much as digits as its factorization.

21211200120133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 21211200120133 its reverse (33102100211212), we get a palindrome (54313300331345).

The spelling of 21211200120133 in words is "twenty-one trillion, two hundred eleven billion, two hundred million, one hundred twenty thousand, one hundred thirty-three".