Base | Representation |
---|---|
bin | 110000001110101000110011… |
… | …100100001010111000001101 |
3 | 1000211000201110100021022000221 |
4 | 300032220303210022320031 |
5 | 210300221110210000023 |
6 | 2031042543540151341 |
7 | 62451411032523532 |
oct | 6016506344127015 |
9 | 1024021410238027 |
10 | 212112120000013 |
11 | 61649276a96692 |
12 | 1b9588bb998551 |
13 | 914811944992c |
14 | 3a543d219ad89 |
15 | 197c7ca27085d |
hex | c0ea3390ae0d |
212112120000013 has 2 divisors, whose sum is σ = 212112120000014. Its totient is φ = 212112120000012.
The previous prime is 212112119999893. The next prime is 212112120000017. The reversal of 212112120000013 is 310000021211212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 195140867534089 + 16971252465924 = 13969283^2 + 4119618^2 .
It is a cyclic number.
It is not a de Polignac number, because 212112120000013 - 233 = 212103530065421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212112120000017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106056060000006 + 106056060000007.
It is an arithmetic number, because the mean of its divisors is an integer number (106056060000007).
Almost surely, 2212112120000013 is an apocalyptic number.
It is an amenable number.
212112120000013 is a deficient number, since it is larger than the sum of its proper divisors (1).
212112120000013 is an equidigital number, since it uses as much as digits as its factorization.
212112120000013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 212112120000013 its reverse (310000021211212), we get a palindrome (522112141211225).
The spelling of 212112120000013 in words is "two hundred twelve trillion, one hundred twelve billion, one hundred twenty million, thirteen", and thus it is an aban number.
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