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2121122013301 = 15114047165651
BaseRepresentation
bin11110110111011100101…
…110010110000001110101
321111202222122021122100201
4132313130232112001311
5234223024213411201
64302232514040501
7306150244426204
oct36673456260165
97452878248321
102121122013301
11748621096125
122a3107579131
13125037039025
147493cc2523b
153a296716801
hex1eddcb96075

2121122013301 has 4 divisors (see below), whose sum is σ = 2135169179104. Its totient is φ = 2107074847500.

The previous prime is 2121122013289. The next prime is 2121122013317. The reversal of 2121122013301 is 1033102211212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2121122013301 - 213 = 2121122005109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2121122013391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7023582675 + ... + 7023582976.

It is an arithmetic number, because the mean of its divisors is an integer number (533792294776).

Almost surely, 22121122013301 is an apocalyptic number.

It is an amenable number.

2121122013301 is a deficient number, since it is larger than the sum of its proper divisors (14047165803).

2121122013301 is a wasteful number, since it uses less digits than its factorization.

2121122013301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14047165802.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2121122013301 its reverse (1033102211212), we get a palindrome (3154224224513).

The spelling of 2121122013301 in words is "two trillion, one hundred twenty-one billion, one hundred twenty-two million, thirteen thousand, three hundred one".

Divisors: 1 151 14047165651 2121122013301