Search a number
-
+
2121132213433 is a prime number
BaseRepresentation
bin11110110111011101010…
…101010000010010111001
321111210000100110212022101
4132313131111100102321
5234223034321312213
64302233520423401
7306150430221202
oct36673525202271
97453010425271
102121132213433
11748626922692
122a310aa77b61
1312503919a9cc
147494031c5a9
153a29757dbdd
hex1eddd5504b9

2121132213433 has 2 divisors, whose sum is σ = 2121132213434. Its totient is φ = 2121132213432.

The previous prime is 2121132213427. The next prime is 2121132213449. The reversal of 2121132213433 is 3343122311212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1977814697104 + 143317516329 = 1406348^2 + 378573^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2121132213433 is a prime.

It is not a weakly prime, because it can be changed into another prime (2121132217433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060566106716 + 1060566106717.

It is an arithmetic number, because the mean of its divisors is an integer number (1060566106717).

Almost surely, 22121132213433 is an apocalyptic number.

It is an amenable number.

2121132213433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2121132213433 is an equidigital number, since it uses as much as digits as its factorization.

2121132213433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 28.

Adding to 2121132213433 its reverse (3343122311212), we get a palindrome (5464254524645).

The spelling of 2121132213433 in words is "two trillion, one hundred twenty-one billion, one hundred thirty-two million, two hundred thirteen thousand, four hundred thirty-three".