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212121025531411 is a prime number
BaseRepresentation
bin110000001110110001000110…
…011000000100111000010011
31000211001120102222121011111011
4300032301012120010320103
5210300342330014001121
62031051015344431351
762452144520351113
oct6016610630047023
91024046388534434
10212121025531411
1161652026a24197
121b95a586318557
139148c08472039
143a549d8c21043
15197cb4bedb7e1
hexc0ec46604e13

212121025531411 has 2 divisors, whose sum is σ = 212121025531412. Its totient is φ = 212121025531410.

The previous prime is 212121025531367. The next prime is 212121025531523. The reversal of 212121025531411 is 114135520121212.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 212121025531411 - 213 = 212121025523219 is a prime.

It is a super-3 number, since 3×2121210255314113 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (212121025561411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106060512765705 + 106060512765706.

It is an arithmetic number, because the mean of its divisors is an integer number (106060512765706).

Almost surely, 2212121025531411 is an apocalyptic number.

212121025531411 is a deficient number, since it is larger than the sum of its proper divisors (1).

212121025531411 is an equidigital number, since it uses as much as digits as its factorization.

212121025531411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 212121025531411 its reverse (114135520121212), we get a palindrome (326256545652623).

The spelling of 212121025531411 in words is "two hundred twelve trillion, one hundred twenty-one billion, twenty-five million, five hundred thirty-one thousand, four hundred eleven".