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212121029983 = 1511404775033
BaseRepresentation
bin1100010110001101100…
…1100000110101011111
3202021112002010210202211
43011203121200311133
511433410440424413
6241240321501251
721216362001562
oct3054331406537
9667462123684
10212121029983
1181a61878455
123513aaa1827
131700657b675
14a3a3c064d9
1557b765083d
hex3163660d5f

212121029983 has 4 divisors (see below), whose sum is σ = 213525805168. Its totient is φ = 210716254800.

The previous prime is 212121029969. The next prime is 212121030013. The reversal of 212121029983 is 389920121212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212121029983 is a prime.

It is a super-3 number, since 3×2121210299833 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212121009983) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 702387366 + ... + 702387667.

It is an arithmetic number, because the mean of its divisors is an integer number (53381451292).

Almost surely, 2212121029983 is an apocalyptic number.

212121029983 is a deficient number, since it is larger than the sum of its proper divisors (1404775185).

212121029983 is a wasteful number, since it uses less digits than its factorization.

212121029983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1404775184.

The product of its (nonzero) digits is 31104, while the sum is 40.

The spelling of 212121029983 in words is "two hundred twelve billion, one hundred twenty-one million, twenty-nine thousand, nine hundred eighty-three".

Divisors: 1 151 1404775033 212121029983